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1 National Agricultural Research Center for Hokkaido Region, 1 Hitsujigaoka, Toyohiraku, Sapporo, Japan 062-8555
2 Dairy and Swine Research and Development Centre, Agriculture and Agri-Food, Canada
Corresponding author: K. Togashi; e-mail: tkenji{at}naro.affrc.go.jp.
| ABSTRACT |
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Key Words: selection intensity selection index persistency lactation curve
Abbreviation key: RR = random regression
| INTRODUCTION |
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Genetic correlations between first lactation milk yield and persistency depend on the measures of persistency used (Swalve and Gengler, 1999; Jakobsen et al., 2002). Two equivalent selection procedures for simultaneous improvement of lactation milk yield and persistency (Lin and Togashi, 2002; Togashi and Lin, 2003) have been presented: index selection based on stage EBV and index selection based on random regression (RR) coefficients from a test day model (Schaeffer and Dekkers, 1994; Jamrozik et al., 1997). Both procedures were developed to achieve prespecified stage gains. However, there are many possible lactation curves that could satisfy the prespecified stage gains, especially when each stage is long. Therefore, it is important to develop an "ideal" index to fulfill the prespecified stage gains with the lowest selection intensity. The objective of this study was to develop a selection index to realize the prespecified stage gains with the lowest selection intensity. A numerical example is given to demonstrate the approach.
| MATERIALS AND METHODS |
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Selection Intensity
Correlated response for day i across lactation (i = 5, 6, ..., 305) because of conventional selection on lactation EBV was estimated as
c = GL(
/
EBVL), where
c is a vector of correlated responses from d 5 to 305, GL is a (301 x 301) genetic covariance matrix of daily yields, 1 is a summing vector of 1 with dimension equal to the number of days from DIM 5 ~ 305,
is the intensity of selection, and
EBVL is the standard deviation of lactation EBV.
EBVL is estimated as
where K is the k x k genetic covariance matrix of RR coefficients with (k 1) being the order of polynomials fitted,
is a 301 x k matrix of Legendre polynomials evaluated from DIM 5 ~ 305. The new lactation curve after one cycle of selection on 305-d milk is the sum of the original lactation curve before selection and correlated responses for each day of the lactation.
Index selection based on stage EBV (I), (Lin and Togashi, 2002; Togashi and Lin, 2003) with (k 1) orders of Legendre polynomials and s stages is
![]() |
where bj is the index weight for stage j,
i(t) is order i of the Legendre polynomial evaluated at day t standardized,
i is order i of the RR coefficient, and mj and nj are the first and last day of stage j, respectively. In matrix notation, I = b'
where
is a column vector containing the EBV of s stages and b is a vector of index weights. The expected genetic gains for the s stages because of selection on I are
= Gb(
/
1), where vector
is the expected genetic gains for s stages (
G1,
G2, ...,
Gs), G is the genetic covariance matrix of s stages, and
I is the standard deviation of I. Selection intensity (
) required to achieve
can be obtained by setting
=
I. Therefore,
![]() | ([1]) |
![]() | ([2]) |
Selection index based on RR coefficients (I*) is described as
![]() |
Index weights (b*) are given by b* = K1 
, where 
is a (k x 1) vector containing the difference in RR coefficients before and after selection. Thus, selection intensity required to achieve 
is obtained as
=
I* where
![]() | ([3]) |
Minimizing Selection Intensity of an Index to Achieve the Intended Stage Gains
Given a fixed order of RR coefficients and a fixed set of stage genetic gains (
), different combinations of selection differentials on each order of RR coefficients (
i) could satisfy these 2 conditions. An interesting question is which combination is optimal so that it would require the lowest selection intensity of an index to achieve the prespecified stage gains. Lin (1985) showed that 3 different restricted indexes were derived to satisfy the same restriction by placing different emphasis on the index traits, suggesting that given a set of prespecified restriction, the solution to achieve the restriction is not unique. Therefore, there are different sets of 
i (i = 1,2...) that would satisfy a prespecified vector of stage gains
*. Different indexes derived from different sets of 
i (i = 1,2...) which satisfy the same vector of intended stage gains would have different selection intensities. Our goal is to find a vector 
k to construct an index that yields the minimum selection intensity and satisfies the prespecified constraint.
Togashi and Lin (2003) showed that when
=
I*, the vector of expected genetic gains of stages is
= S
k where S is a (s x k) matrix that contains the sum of each order of Legendre polynomials within stages, i.e.,
![]() |
Lagrange multiplier was used to choose a vector 
k so that the index constructed based on
* has a minimum variance with the restriction that the vector of expected stage genetic gains is equal to the vector of intended genetic gains
.
The function to be minimized is
is a vector of Lagrange multipliers.
Setting the partial derivatives of f with respect to 
k equal to zero leads to
![]() | ([4]) |
Setting the partial derivatives of f with respect to
equal to zero leads to
![]() | ([5]) |
Equations [4]
and [5]
can be written jointly as follows:
![]() | ([6]) |
According to the principle of Lagrange multiplier, the solution vector 
k in equation [6]
would lead to minimum selection intensity and satisfy the constraints of the expected genetic gains being equal to the intended genetic gains.
The inverse of the coefficient matrix of equation [6]
can be obtained through inversion by partitioning (Searle, 1966). Therefore, the solution to equation [6]
is
![]() |
The first set of equations is equal to
![]() | ([7]) |
Index coefficients (b*) for the selection index based on RR coefficients are determined by b* = K1 
. Finally, the index based on RR coefficients that would achieve the prespecified stage gains with the lowest selection intensity is
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This is a general case whether the number of stages (s) is equal to that of RR coefficients fitted (k). When s = k, equation [7]
reduces to 
k = S1
* and, subsequently, I* =
'K1S1
*. The correlated response for DIM i (
Ci) from selection on I* is given by
Ci =
'
k (
0(i*)
1(i*) ...
k1(i*))', where i* is standardized time.
Relationship Between I and I* with the Lowest Selection Intensity
Togashi and Lin (2003) showed that a selection index based on RR coefficients (I* =
'b*) is equivalent to a selection index based on stage EBV (I =
'b) and that vector b is equivalent to (SS')1Sb*. These 2 equalities hold true whether these 2 indexes result in minimum selection intensity. When b* used to construct index I* leads to a minimum selection intensity as shown in the preceding section, then b = (SS')1Sb* used to construct index I will also lead to a minimum selection intensity because (SS')1S is a constant independent of the calculation of b and b*. Therefore, b and b* can be easily converted from each other.
Note that b = (SS')1Sb* = (SS')1SS'(SKS')1
* = (SKS')1
* = G1
*. This shows that index I, which was converted from index I* with minimum selection intensity, also has the least intensity of selection.
Numerical Example
As an example, a lactation length of 305 d was partitioned into 3 stages (s = 3): stage 1 (DIM 5 ~ 65), stage 2 (DIM 66 ~ 280), and stage 3 (DIM 281 ~ 305). Assume that the annual genetic gain on a lactation basis is 100 kg EBV and that we want to reduce stage 1 by 25 kg EBV and to improve stage 2 by 125 kg EBV while holding stage 3 to zero change. This means that
.
The genetic covariance matrix (K) of RR coefficients (k = 5) estimated by Pool et al. (2000) based on Dutch test-day data was used to compute the proposed index:
![]() |
As defined previously, matrix S3x5 contains the sum of each order of Legendre polynomials within each of the 3 stages.
![]() |
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Index coefficients (b*) of I* with the lowest selection intensity are
![]() |
Finally,
. Selection intensity (i) to realize the prespecified stage gains
is
![]() |
The correlated response for DIM i (
Ci) is
Ci =
'
5
. For instance, the correlated response for DIM 65 (
C65) is
![]() |
The conversion of b* to b for the index based on stage EBV with the least selection intensity gives
.
Selection intensity (
) for index I is
. Clearly, selection intensity of 1.259 was the same for both I and I* because both indexes are equivalent.
Next, consider selection index (I**) based on RR coefficients with no restriction imposed on the selection intensity (Togashi and Lin, 2003).
![]() |
Index coefficients for I** are
![]() |
and selection intensity (
) is
.
Correlated response for DIM i (
Ci) is equal to
.
For instance,
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EBVL for conventional selection based on 305-d milk EBV is
![]() |
Selection intensity (
) to achieve 100 kg total milk yield is
= 100/
EBVL= 0.149. Correlated response (
c) for each DIM because of conventional selection is
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| RESULTS AND DISCUSSION |
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Togashi and Lin (2003) showed 
= (S'S)1S'
. The index derived based on 
would realize the prespecified stage gains, but there is no guarantee that the index would offer the lowest selection intensity possible. Their approach would result in an index with minimum selection intensity only if the number of stages partitioned is equal to the number of RR coefficients fitted (s = k). In contrast, the index resulting from 
k in equation [7]
of this study provides a unique solution to achieve the prespecified stage gains with minimum selection intensity.
The correlated daily responses across lactation for those I (or I*), I**, and selection based on 305-d lactation milk (EBVL) in numerical example are shown in Figure 1
. The prespecified stage gains for the 3 indexes, I, I*, and I**, are 25, 125, and 0 kg EBV for stage 1 (DIM 5 ~ 65), stage 2 (DIM 66 ~ 280), and stage 3 (DIM 281 ~ 305), respectively. The daily genetic response because of selection on I** (without restriction on selection intensity) changes more drastically than that caused by selection on I (I*) or EBVL. The fluctuating pattern of daily genetic responses for I** would yield a larger genetic deviation across the lactation and require a higher selection intensity than I (I*) to achieve the selection goal. Daily genetic gains because of selection on EBVL are almost at the same level throughout the lactation because selection on EBVL imposes no restriction and have no control over daily genetic responses.
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In the numerical example, prespecified absolute gains for the 3 lactation stages are assumed to be
, which is equal to
. Note that the common factor of 5 can be dropped without affecting the proportionality of the index (b or b*). Therefore, the imposition of prespecified absolute gains is in fact equivalent to the restriction of prespecified relative changes of
. However, pre-specified absolute gains of
with a total of 100 kg EBV should be used to ensure a fair comparison with conventional selection for lactation response of 100 kg EBV in the numerical example.
| CONCLUSIONS |
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| ACKNOWLEDGEMENTS |
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| FOOTNOTES |
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Received for publication January 27, 2004. Accepted for publication April 20, 2004.
| REFERENCES |
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